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what does this production function look like on a graph?
f(x1, x2) = 12x1^(1/2) + 4x2^(1/2) -
That would be a 3 dimensional graph. Do you have a graphing calculator?
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Not with me, what about if the last term, 4x2^(1/2) is left out of the equation, where output is y-axis and x1 is x-axis?
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without the last term the equation is:
f(x1, x2) = 12x1^(1/2)
in 3 dimensions that is z = 12x^(1/2)
which is just like y = 12x^(1/2) just graph it along the Z and X axis
Z|
|
|
|
|___________ y axis
/
/
/
/ x axis -
I'm installing matlab on my new computer right now so that I can graph it ;)
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If i remember correctly... matlab is the devil.
p.s. your such a nerd, lol. -
If it makes you feel better I didn't pay for it!
And it has all of the expensive expansion packs hehehe. -
oops that obv ya i knew that.. thanks 4 the help
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oh it's cool man you don't need to do that.. I'm trying to find where marginal product of factor 1 is = to a line with the a slope of 1/4
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try not to go out of an OT tourney in 30 seconds next time k?
its all ur fault i cant play now. -
loooool
whoops. -
on that graph x1 is the horizontal axis that goes up and to the right, and x2 is the horizontal axis that goes up and to the left. Z is vertical.
I forgot to label them. -
thanks man - could you tell me what dy/dx1 is?
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do you mean df/dx1? There is no y in your problem.
df/dx1 = 12*(1/2)*x1^(-1/2)
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