Check out our brand new Local Poker Communities! Get updates and interact with poker players in your area.
Visit the United States Poker Community | Visit the California Poker Community | Read more about the Launch of P5s Local
  1. what does this production function look like on a graph?

    f(x1, x2) = 12x1^(1/2) + 4x2^(1/2)
  2. That would be a 3 dimensional graph. Do you have a graphing calculator?
  3. Not with me, what about if the last term, 4x2^(1/2) is left out of the equation, where output is y-axis and x1 is x-axis?
    Thread Starter
  4. Then it would look like the graph of squareroot of x with magnitude 12 times greater.



    That's what sqrt(x) looks like. I hope you know that part at least.
  5. without the last term the equation is:

    f(x1, x2) = 12x1^(1/2)

    in 3 dimensions that is z = 12x^(1/2)

    which is just like y = 12x^(1/2) just graph it along the Z and X axis

    Z|
    |
    |
    |
    |___________ y axis
    /
    /
    /
    / x axis
  6. i have one lol $5 and ill let you borrow it :-p

     
    Originally Posted by steveyB View Post


    Not with me, what about if the last term, 4x2^(1/2) is left out of the equation, where output is y-axis and x1 is x-axis?

  7.  
    Originally Posted by brianyut View Post

    That would be a 3 dimensional graph. Do you have a graphing calculator?

    Man your good. I didnt remember this one.

    The last time I remember graphing anything in 3D was prolly freshman year.
  8. I'm installing matlab on my new computer right now so that I can graph it ;)
  9. If i remember correctly... matlab is the devil.

    p.s. your such a nerd, lol.
  10. If it makes you feel better I didn't pay for it!

    And it has all of the expensive expansion packs hehehe.
  11. oops that obv ya i knew that.. thanks 4 the help
    Thread Starter
  12.  
    Originally Posted by steveyB View Post

    oops that obv ya i knew that.. thanks 4 the help

    give me 5-10 mins and I will give you a picture of the graph from matlab.
  13. oh it's cool man you don't need to do that.. I'm trying to find where marginal product of factor 1 is = to a line with the a slope of 1/4
    Thread Starter
  14. try not to go out of an OT tourney in 30 seconds next time k?

    its all ur fault i cant play now.
  15. loooool

    whoops.
  16. Here's the graph of the fcn in the OP:

  17. on that graph x1 is the horizontal axis that goes up and to the right, and x2 is the horizontal axis that goes up and to the left. Z is vertical.

    I forgot to label them.
  18. thanks man - could you tell me what dy/dx1 is?
    Thread Starter
  19. do you mean df/dx1? There is no y in your problem.

    df/dx1 = 12*(1/2)*x1^(-1/2)

Similar Threads