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try and calculate these odds...

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  1. uscsteve uscsteve is offline

    Fairport, NY
    United States

    Posts: 95
    Joined: Mar 06

    Feb 1st, 2007 (2/1/2007 12:58pm)

    In 97 hands I received:

    AA - 4 times
    KK - 2 times
    QQ - 1 time
    JJ - 3 times
    99 - 1 time

    I've had many games where I received a lot of pp's, even high ones like this but it just seemed
    so weird to happen like this. Does anyone know how to calculate the odds of this happening?
  2. godseyt godseyt is offline

    Hilliard, OH
    United States

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    Feb 1st, 2007 (2/1/2007 1:05pm) in reply to uscsteve

    14
  3. Rocket Surgeon Rocket Surgeon is offline & brain scientist

    United States

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    Feb 1st, 2007 (2/1/2007 1:13pm) in reply to godseyt

    See, that's where you are wrong godseyt, it's clearly 50%, it happens or it doesnt.
  4. Arobinson11 Arobinson11 is offline

    Round Rock, TX
    United States

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    Feb 1st, 2007 (2/1/2007 1:23pm) in reply to Rocket Surgeon

    lol
     1
  5. IagoX9 IagoX9 is offline

    Colorado Springs, CO
    United States

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    Feb 1st, 2007 (2/1/2007 1:51pm) in reply to uscsteve

    (1/221)^11*(1-5*(1/221))^86=.0000000000000000000000000227%

    that is if you get dealt those hands exactly 11 times and get dealth any other hand (except those hands) 86 times
  6. uscsteve uscsteve is offline

    Fairport, NY
    United States

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    Feb 1st, 2007 (2/1/2007 1:54pm) in reply to IagoX9

    OK....what about the odds of getting a pocket pair 10's or higher (even though I did not recieve 10's) 10 of 97 hands.
    Thread Starter
  7. IagoX9 IagoX9 is offline

    Colorado Springs, CO
    United States

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    Feb 1st, 2007 (2/1/2007 2:03pm) in reply to uscsteve

    again assume you get 10s or higher exactly 10 times out of 97 hands:

    (5*1/221)^10*(1-5*(1/221))^87=.000000000000000048%
  8. slasher72 slasher72 is offline

    Vancouver
    Canada

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    Joined: Dec 05

    Feb 1st, 2007 (2/1/2007 2:15pm) in reply to uscsteve

    Excellent question for us math weirdos....If someone is better at this than I and I have it wrong please correct, but I think that it goes something like this:

    Odds of a specific pocket pair = 220:1 for a given hand

    Assuming that you want to know the specific odds for this allocation of hands and not just the odds of getting 11 pocket pairs over 99, then it goes something like this:

    AA - 4 times in 97 hands is (220:1 *4 / 97)= 9.07% chance (11:1)
    KK - 18% chance (5.5:1)
    QQ - 36% chance (2.25:1)
    JJ - 14% chance (6.8:1)
    99 - 36% chance (2.25:1)

    So, the specific sequence that you outlined has a chance of 2082:1 of happening. Having 11 pocket pairs is much more straight forward at odds of 4.5:1 of getting one of these pairs on each hand. 11 instance in 97 hands has odds of 196:1

    Hope that helps and if I'm wrong can someone with a greater mathematical knowledge correct me...
  9. brsavage brsavage is online now Spontaneous Benefactor

    Denham Springs, LA
    United States

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    Feb 1st, 2007 (2/1/2007 2:24pm) in reply to uscsteve

    If you are not lying, looks to me like the odds are exactly 100%
     1
  10. uscsteve uscsteve is offline

    Fairport, NY
    United States

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    Feb 1st, 2007 (2/1/2007 3:50pm) in reply to brsavage

    This did indeed happen. I went heads up against a guy on UB named Poker4_____(can't remember the last part of his name). I showed when I got these hands after the first couple times as it was kinda crazy how I was getting them.

    Thanks for all the help from the math knowledgeable. Perhaps I should go back to school, some of that stuff was pretty hard for me to follow! :)
    Thread Starter
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