Poker Discussion
|
|
Please help support pocketfives by using our links when choosing to download a new site!
CarbonPoker · Full Tilt · Cake Poker · PokerStars · Ultimate Bet · Players Only · Bodog
|
Question
|
Kyle XY
(United States)
480
Posts.
Joined
07-08-2005.
03-14-2009 3:50 AM
|
|
|
|
I was having a debate with a few friends; the question is, if you select 3 cards, lets say for instance the 2 7 and Jack, what is the chance one of the 3 will be on the flop? My assumption was it would be 9/13 times, since its 3/13 + 3/13+ 3/13, thus making it that, but does seem a bit high; Anyone know for certain, I know awfully easy question, but figured why not ask to make sure. Thank you in advance
|
|
|
|
|
9 cards that pair. 49 cards left that we dont know. 9/49+9/48+9/47 Subtract one for each known card on flop that doesnt pair obv. About 54%
|
|
|
|
wait, how is it 9 cards that pair? u just randomly deal a flop is what I am referring to, you do not have a 2 7 or J in your hand, but merely are betting whether any of the 3 will show, thus isnt it 12 cards, since 4 of each, and thus make it 12/52+12/51+12/50?
|
|
|
|
yes there are 12 2's, 7's, and J's combined. You have 3 of them in your hand though. So there are only 9 left in the deck out of the 49 remaining cards.
|
|
|
|
Hmm, you don't have any in your hand, im saying you shuffle a deck, and then just deal the flop, so basically all the cards are fair game.
|
|
|
|
depends who is cutting the deck.
|
|
|
|
|
Sortable Rankings
|
|
|
|
|
|
|
|
|